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Old 08-14-2004, 05:07 PM
Gabourie Gabourie is offline
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Join Date: Feb 2004
Posts: 27
Gabourie
Default acid copper / power requirements

The resistor trick is working great. I have also found that in the flash copper tank when I am plating a small part (36sq") I needed to put the resistor in series to get the power supply to start on a low current. It will adjust out at 3 and up amps but that is way too much for this size. Put the resistor in and no problem I can get it to go to 2.6 amps.
Regarding using a larger piece in the acid tank, math is not one of my strong points but according to my calculations using the 1 amp per 10-15sq" guide in the manual 12 x 12 = 144 / 15 = 9.6 amps. Applying that number in your formula
300 sq" / 144 sq" = 2.08 sq '
2.08 sq' x 9.6A/sq' = 19.96A
R=1V/19.96A = 0.5 Ohms. W = 1V x 9.6A = 9.6 Watts ?
(was the 2A per sq ft. just an example? or where is that number from?)
Is that correct 9.6 amps per sq. foot?
Who would of thought a hobby would turn into a math class .

Thanks again.
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