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Old 09-02-2004, 12:06 PM
Fibergeek Fibergeek is offline
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A power supply like that one is what you want.

We determined at the start of this thread that you needed a minimum of 27.4A to anodize 4.56 sq.ft. at 6ASF. This corresponds to a maximum Voltage of 13.2V. We also agreed that you should have some margin, so we bumped up the maximum Voltage to about 15V. This will require 27.4A x 15V = 411W. This is going to get expensive.

We then agreed that a reasonable compromise would be to do the anodizations 1 piece at a time. Since the largest piece is 1.98 sq.ft. the power requirements are now 11.9A and 15V, which is 11.9A x 15V = 179W. This will cost less.

If you had a 10A power supply, you would need to reduce the current density to 6 ASF x 10A / 11.9A = 5 ASF. 5 ASF is within the LCD range so this will be OK.

When all of this makes sense to you; and you understand how to adjust the process without getting into trouble, you can optimize it to suit your particular application. At this point, you can make the necessary process adjustments to speed it up considerably, and you will know how. Or maybe you will decide that that it will be too expensive and you will live with the anodization time. Either way you will be successful.
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