16 sq. cm. = 2.48 sq. in. = .0172 sq. ft.
0.74A / .0172 sq. ft. = 43A per sq. ft.
That's an awfully high current density, it would require:
2.5 Ohms / sq. ft. x 43 A / sq.ft. = 107V to grow the anodize to full potential thickness. You probably don't have that much.
4.5 A / sq. ft. current density for 16 sq. cm. would require 77.4 mA.
Your acid concentration should be about 5% at this current density.
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