I haven't started my ano line yet, just want to get an idea of how big of a power supply I need by measuring a few scrap pieces I have laying around. I just wanted to make sure I'm calculating the surface area correctly, so if someone could double check this for me would be great, thanks
This is a piece of aluminum pipe
2.9" outer diameter
2.5" inner diameter
2.35" hight
.2" wall thickness
2.9x3.14= 9.11" Outer Circumference
2.5x3.14= 7.85" Inner Circumference
9.11x2.35= 21.41" outer surface area
7.85x2.35= 18.45" inner surface area
2.9/2=1.45" outer radius
2.5/2=1.25" inner radius
(A= pi r2) 3.14(1.45x1.45)= 6.6" surface area of outer circle (top/bottom)
(A= pi r2) 3.14(1.25x1.25)= 4.9" surface area of inner circle (top/bottom)
Subtract inner circle area from outer to get wall surface area x2
6.6-4.9= 1.7 x2= 3.4" top and bottom edge surface area
3.4 + 21.41 + 18.45 = 43.26 square inches?
43.26 x .0069 = .3 square feet?
720 rule calculator
at 4.5 ASF @ 1mil = 1.35A for 120mins?
Any easier way to do this? My brain hurts...
What do you guys do for irregularly shaped objects? This was a simple piece and took some serious brain power even with a calculator! I'm sure it'll get easier the more I do it though.


LinkBack URL
About LinkBacks





Reply With Quote


Bookmarks