I have built a 12 volt lamp controller capable of 100 Amps. The problem is that the meters on the market can only measure 10 amps. I have heard it is possible to do using resistors. Does anyone know how to do this ?
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Re: Measure 100 amps with 10 amp meter ?
Your meter has an internal shunt (resistor) which the meter uses to measure the current. What you need to do is attach a second shunt resistor in parallel with the meter. If the second shunt resistor has 1/9th the resistance of the meters shunt, the meter will read 1/10th the actual current flowing. And this second shunt would have to be rated for 90A or more.

Re: Measure 100 amps with 10 amp meter ?
eprigge:
If the second shunt resistor has 1/9th the resistance of the meters shunt, the meter will read 1/10th the actual current flowing.
The formula for parallel resitance is: (R1 X R2)/(R1 + R2)
In order to read 10x the original amperage, you need 1/10 the original shunt resistance. Your numbers produce just under 1/5 the resistance, and the meter would be way off.
The correct value for the second resistor would be @ 0.11 x the first value
MotoChrome:
The problem is that the meters on the market can only measure 10 amps. I have heard it is possible to do using resistors. Does anyone know how to do this ?
Is it a digital or analog meter?
All digital meters are shunt type, but some are sealed so that you can't take them apart to find the resistance.
Analog meters are either shunt or series.
A series analog meter does not use a shunt resistor, you have to determine the resistance of the internal coils. Not easy. But the resistance MIGHT be marked on the face plate.
A shunt analog meter may have an external or internal shunt. If it's external, disconnect it and measure its resistance. If it's internal, you will have to disassemble the meter to get at it.
Once you've determined the original resistance, find a resistor of 0.11 x that value, and use it in parallel with the meter. You want a precision resistor, of 1% tolerance or better, which is temperature stable.
The wattage will depend on your maximum PS voltage. As eprigge said, the new resistor will carry 90 amps. Multiply that by your max voltage, and that will give you the MINIMUM wattage for the resistor.
eg. if you'll be plating @ 12v, then 12x90= 1080 watts. That would be a HUGE and EXPENSIVE resistor.
SeanSeans Zinc Plating page
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Re: Measure 100 amps with 10 amp meter ?
There's an easier way to do it, just find a shunt resistor with a known (small) value of resistance, say 0.1 ohms. Then when you have current flowing, you measure the voltage across the shunt, with the meter in the volts position (not in the amps position).
E = Voltage
I = current
R = resistance
E=IR
R=E/I
I=E/R
So, to find current, if you read 10V on the voltmeter (example), the current is 100A (if the shunt is 0.1 ohms).
SteveSteve Dold
http://stevedold.com
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Re: Measure 100 amps with 10 amp meter ?
I forgot:
power = E x I
So the 0.1 ohm resistor would have to dissipate 100amps x 10V, = 1000W.
It would be an impressive resistor!Steve Dold
http://stevedold.com
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Re: Measure 100 amps with 10 amp meter ?
Originally posted by seanceprigge:
Your values are off.
The formula for parallel resitance is: (R1 X R2)/(R1 + R2)
In order to read 10x the original amperage, you need 1/10 the original shunt resistance. Your numbers produce just under 1/5 the resistance, and the meter would be way off.
The correct value for the second resistor would be @ 0.11 x the first value
I would hazard a guess that a DMMs 10A range shunt resistance is around 0.01 ohms. Any more than that and you'd have too much power dissipating inside the meter. You might be able to find out from the meter docs or the manufacturer instead of measuring it yourself. If it was 0.01 ohms then the second shunt would need to be 0.00111 ohms and would need to handle 9 watts to carry 90A.
I would use a constant, known current source like a current controlled power supply to make the new shunt. It's such a low resistance you will probably just make it out of a length of copper wire. If you know you've got 10A flowing through the load, diddle with the shunt resistance until your meter reads 1.00. Voila. In the example above, about a foot of 1012 gauge wire would be in the 0.001 ohm ballpark.Last edited by eprigge; 10202005, 02:41 PM.
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Re: Measure 100 amps with 10 amp meter ?
Originally posted by epriggeNo, my numbers are right
SeanSeans Zinc Plating page
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Re: Measure 100 amps with 10 amp meter ?
Steve:
Originally posted by sdoldThere's an easier way to do it, just find a shunt resistor with a known (small) value of resistance, say 0.1 ohms.
I got a surplus 200mA digital panel meter, which used a 1ohm shunt (the actual meter was a 200mV full scale "movement"). Wired in additional 0.1 & 0.01 ohm resistors through a switch, and now have a switchable 20A, 2A, 200mA dedicated ammeter.
SeanSeans Zinc Plating page
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Re: Measure 100 amps with 10 amp meter ?
Originally posted by seancSteve:
That's all a digital ammeter is: a voltmeter w/a builtin shunt.
Sean
SteveLast edited by sdold; 10212005, 01:33 AM.Steve Dold
http://stevedold.com
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Re: Measure 100 amps with 10 amp meter ?
Steve:
Yep, a multimeter works great, but sometimes it's not convenient.
In my case, I only have one DMM, and I use it for a lot of other things besides plating, so the dedicated amp meter relieved me of constantly switching the meter around.
But the price of some of these offshore DMMs is so cheap anymore, it might be worth it to get a few of them for dedicated purposes.
SeanSeans Zinc Plating page
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Re: Measure 100 amps with 10 amp meter ?
Yeah, no kidding, they are cheap
I thought he was looking for a multimeter, since he said everything he was seeing was 10A, which sounds like the typical DMM. I might have been wrong.
Maybe he could just get a panelmounted meter, aren't they something like 050 microamps? And put some kind of shunt around that. For a hundred amps, maybe a 1inch piece of copper bar would be about rightSteve Dold
http://stevedold.com
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Re: Measure 100 amps with 10 amp meter ?
Steve:
I didn't read his post carefully enough. I though he already HAD the 10A meter.
I don't know that analog panel meters have any standard rating, but every digital panel meter I've seen has always been based on a 200mV full scale volt meter. You know, the 01.999 4digit type.
Both ammeter and voltmeter are the same except the input wiring. The voltmeter is wired as a 2 resistor voltage divider, while the ammeter is just a shunt resistor. Otherwise, both meters are identical 200mV volt meters.
Copper pipe would work! Or tie into a chunk of the house plumbing and heat your water while you're plating!
Seriously, a large low resistance might possible without too much expense, if you can find the right value parts. I once racked up some 15 ohm , 50w power resistors (the gold aluminum heat sink type) for an amplifier dummy load. 16 of them gave me 800w of dissipation. They were cheap surplus, 50? each.
If you could find them in 1 or .1 ohm values, a rack of them would work, and give you a nice hot plate to boot!
SeanSeans Zinc Plating page
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Re: Measure 100 amps with 10 amp meter ?
In the end it doesn't really matter whether you have a DMM in current or voltage mode or a panel meter or what, you still need to buy/make a very low value high power shunt for the meter. You don't want anything much over 0.001 ohms just because of heat dissipation.
Again I'd suggest using a length of 1012 (or thicker) gauge wire as the shunt. If you can get a known value current source from a power supply, you should be able to make your own shunt to work very accurately with whatever meter you choose.
There usually several power shunts made for this purpose on ebay also.
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Re: Measure 100 amps with 10 amp meter ?
1 foot of 10 gage copper wire is .00118 ohms. From this you can easily figure amps by measuring the voltage drop across the wire.HobbyTalk Forums: Diecast Collecting  Model Building  Radio Control Vehicles  Slot Cars  Small Engine Repair
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